Given the code fragment:System.out.println(2 + 4 * 9 – 3); //Line 21 System.out.println((2 + 4) * 9 – 3); // Line 22 System.out.println(2 + (4 * 9) – 3); // Line 23 System.out.println(2 + 4 * (9 – 3)); // Line 24 System.out.println((2 + 4 * 9) – 3); // Line 25Which line of codes prints the highest… Read More »
Given:What is the result?Compilation fails at line n3 and line n4. A. Compilation fails at line n1 and line n2. B. Welcome Visit Count:1 C. Welcome Visit Count: 1Welcome Visit Count:1 D. Welcome Visit Count: 2 Correct Answer: B
Given the code fragment from three files:Which code fragment, when inserted at line 2, enables the code to compile? A. Option C B. Option B C. Option A D. Option D E. Option E Correct Answer: E
Given:What must be added in line 1 to compile this class? A. catch(FileNotFoundException | IOException e) { } B. catch(IndexOutOfBoundsException e) { }catch(FileNotFoundException e) { } C. catch(FileNotFoundException e) { }catch(IndexOutOfBoundsException e) { } D. catch(IOException e) { } E. catch(FileNotFoundException | IndexOutOfBoundsException e) { } Correct Answer: D
Given:When run and all three files exist, what is the state of each reader on Line 1? A. The compilation fails. B. All three readers are still open. C. All three readers have been closed. D. Only reader1 has been closed. Correct Answer: A
Given the code fragment:Which code fragment, inserted at line n1, prints The Top element: 30? A. Option A B. Option B C. Option C D. Option E E. Option D Correct Answer: D
Given:Which statement is equivalent to line 1? A. double totalSalary = list.stream().map(e > e.getSalary() * ratio).reduce (bo).ifPresent (p > p.doubleValue()); B. double totalSalary = list.stream().mapToDouble(e > e.getSalary() * ratio).sum; C. double totalSalary = list.stream().map(Employee::getSalary * ratio).reduce (bo).orElse(0.0); D. double totalSalary = list.stream().mapToDouble(e > e.getSalary() * ratio).reduce(starts, bo); Correct Answer: C
Given:Which statement is equivalent to line 1? A. double totalSalary = list.stream().map(e -> e.getSalary() * ratio).reduce (bo).ifPresent (p -> p.doubleValue()); B. double totalSalary = list.stream().mapToDouble(e -> e.getSalary() * ratio).sum; C. double totalSalary = list.stream().map(Employee::getSalary * ratio).reduce (bo).orElse(0.0); D. double totalSalary = list.stream().mapToDouble(e -> e.getSalary() * ratio).reduce(starts, bo); Correct Answer: C
Given:Which statement on line 1 enables this code fragment to compile? A. Function function = String::toUpperCase; B. UnaryOperator function = s > s.toUpperCase(); C. UnaryOperator<String> function = String::toUpperCase; D. Function<String> function = m > m.toUpperCase(); Correct Answer: C
Given:Which statement on line 1 enables this code to compile? A. Function<Integer, Integer> f = n > n * 2; B. Function<Integer> f = n > n * 2; C. Function<int> f = n > n * 2; D. Function<int, int> f = n > n * 2; E. Function f = n > n * 2; Correct… Read More »